Canadian Forces Aptitude Test (CFAT) Practice

Question: 1 / 400

What is the total surface area of a box with doubled dimensions if the original dimensions are 3 cm wide, 2 cm deep, and 4 cm high?

96 cm²

208 cm²

To determine the total surface area of a box with doubled dimensions, we first need to calculate the surface area of the original box, which has dimensions of 3 cm wide, 2 cm deep, and 4 cm high.

The formula for the surface area \(S\) of a rectangular box is:

\[ S = 2(lw + lh + wh) \]

where \(l\) is the length, \(w\) is the width, and \(h\) is the height.

Using the original dimensions:

- Length = 4 cm (height)

- Width = 3 cm

- Height = 2 cm (depth)

Calculating the surface area of the original box gives us:

- \( lw = 4 \times 3 = 12 \)

- \( lh = 4 \times 2 = 8 \)

- \( wh = 3 \times 2 = 6 \)

Now substituting back into the formula:

\[ S = 2(12 + 8 + 6) = 2(26) = 52 \, \text{cm}² \]

Next, we double the dimensions:

- New width = 3 cm × 2 =

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144 cm²

72 cm²

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